Y=3x^2+5-1

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Solution for Y=3x^2+5-1 equation: 



=3Y^2+5-1

We move all terms to the left:

-(3Y^2+5-1)=0

We get rid of parentheses

-3Y^2-5+1=0

We add all the numbers together, and all the variables

-3Y^2-4=0

a = -3; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-3)·(-4)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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